Number of 4 digit no.Having only 3 consecutive digits
Chepuri Manikanta , 5 Years ago
Grade 12th pass
Algebra> Number of 4 digit no. Having only 3 conse...
1 Answers
ADARSH SINGH
Last Activity: 5 Years ago
THE CORRECT ANSWER IS 70+72= 142 ….
LOOK HOW ,
YOU HAVE 4 PLACES TO FILL WITH NUMBERS , AND 3 PLACES ARE HAVING CONSECUTIVE NUMBERS. NOW EITHER FIRST THREE NUMBERS ARE CONSECUTIVE OR NEXT THREE NUMBERS ARE CONSECUTIVE .
IF FIRST THREE NUMBERS ARE CONSECUTIVE ,
FIRST NUMBER CAN BE ANY OF 1 TO 7 , NOT MORE THAN 7 , BECAUSE THEN YOU WILL NOT GET 2 CONSECUTIVE INTEGERS FOR FILLING .
NOW THE NEXT 2 DIGITS WOULD BE UNIQUE AND FIXED DEPENDING ON THE FIRST DIGIT.
THE LAST DIGIT COUOD BE ANY OF 0 TO 9 (TOTAL 10 NUMBERS)
HENCE , BY MULTIPLICATION PRINCIPLE, TOTAL CASES POSSIBLE ARE 70.
similarly IN SECOND CASE , FIRST NUMBER COULD BE ANY ONE OF 1 TO 9 , AND THE NEXT COULD BE ANY OF 0 TO 7 (TOTAL 8 ) HENCE TOTAL POSSIBLE CASES BY MULTIPLICATION PRINCIPLE ARE 72
HENCE THE REQUIERES ANSWER IS 70 + 72 = 142 .
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