loga/b-c=logb/c-a=logc/a-b,then the value of a^a.b^b.c^c is equal to

let us consider every ratio is equal to some constant k

loga/b-c=logb/c-a=logc/a-b=k

then 

loga=k(b-c)

logb=k(c-a)

logc=k(a-b)

now multiply  equation by a,b,c respestively

aloga=k(ab-ac)

blogb=k(bc-ab)

clogc=k(ac-bc)

add all the three equations

we get 

aloga+blogb+clogc=k(ab-ac+bc-ab+ac-bc)

log(a^ab^bc^c)=0

s0

a^ab^bc^c =1

simple right

plzzz approve it means a lot to me

ENJOY LERANING