let n be a odd natural no. greater than 1. then the no. of zeros at the end of the sum 99 n +1 is 1)3 2)4 3)2 4)none

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Vijay Mukati · Answer

Ans &ndash; 3) 2 Explanation. x^n + y^n is always divisible by (x+y) for n to be any odd number.

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let n be a odd natural no. greater than 1. then the no. of zeros at the end of the sum 99 n +1 is 1)3 2)4 3)2 4)none

let n be a odd natural no. greater than 1. then the no. of zeros at the end of the sum 99ⁿ +1 is
1)3
2)4
3)2
4)none

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let n be a odd natural no. greater than 1. then the no. of zeros at the end of the sum 99 n +1 is 1)3 2)4 3)2 4)none

let n be a odd natural no. greater than 1. then the no. of zeros at the end of the sum 99n +1 is1)32)43)24)none

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let n be a odd natural no. greater than 1. then the no. of zeros at the end of the sum 99ⁿ +1 is
1)3
2)4
3)2
4)none