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`        If z= x- iy and z^3 = p+IQ then x÷p+ y÷q÷p^2 + q^2 is equal to`
11 months ago

```							Z=x+iy and z¹/³=p+iq∴, (x+iy)¹/³=p+iqCubing both sides,x+iy=(p+iq)³or, x+iy=p³+3p²iq+3p(iq)²+(iq)³or, x+iy=p³+3ip²q-3pq²-iq³  [i²=-1]or, x+iy=(p³-3pq²)+i(3p²q-q³)Equating the real and imaginary parts from both sides,x=p³-3pq² and y=3p²q-q³∴, (x/p+y/q)/(p²+q²)=[(p³-3pq²)/p+(3p²q-q³)/q]/(p²+q²)=(p²-3q²+3p²-q²)/(p²+q²)=(4p²-4q²)/(p²+q²)=4(p²-q²)/(p²+q²)
```
11 months ago Saurabh Koranglekar
8366 Points
```							Dear studentPlease repost using brackets, that it is clear what the exact question isHoweverP = (cube(x)) - ((3x)*(sqr(y)))Q = (cube(y)) - ((3y)*(sqr(x)))Regards
```
11 months ago
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