If X=log a (bc), Y=log b (ac) , Z=log c (ab) , then 1/(X+1) + 1/(Y+1)

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If X=log a (bc), Y=log b (ac) , Z=log c (ab) , then 1/(X+1) + 1/(Y+1) + 1/(Z+1) is equal to? (A) 0 (B) 2 (C) 4

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