if x is a real number and [x+(11/100)] + [x+(12/100)] + …...............[x+(99/100)] = 765 then find the value of [900] – [100x] where [.] represents greatest integer.

Question

Kushal Upadhyay · Answer

(X+11/100)+(X+12/100)+....+(X+99/100)=765 Hence (100x+11+100x+12+100x+13+...+100x+99)/100=765 Now,there are 89 100x terms and by cross multiplying 76500=8900x+4895 Now we get,X=8.04 900-(100×8.04). Hence we get 96 as answer.

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if x is a real number and [x+(11/100)] + [x+(12/100)] + …...............[x+(99/100)] = 765 then find the value of [900] – [100x] where [.] represents greatest integer.

if x is a real number and [x+(11/100)] + [x+(12/100)] + …...............[x+(99/100)] = 765 then find the value of [900] – [100x] where [.] represents greatest integer.

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if x is a real number and [x+(11/100)] + [x+(12/100)] + …...............[x+(99/100)] = 765 then find the value of [900] – [100x] where [.] represents greatest integer.

if x is a real number and [x+(11/100)] + [x+(12/100)] + …...............[x+(99/100)] = 765 then find the value of [900] – [100x] where [.] represents greatest integer.

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