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if x is a real number and [x+(11/100)] + [x+(12/100)] + …...............[x+(99/100)] = 765 then find the value of [900] – [100x] where [.] represents greatest integer.
9 months ago

7 Points

(X+11/100)+(X+12/100)+....+(X+99/100)=765
Hence (100x+11+100x+12+100x+13+...+100x+99)/100=765
Now,there are 89 100x terms and by cross multiplying
76500=8900x+4895
Now we get,X=8.04
900-(100×8.04). Hence we get 96 as answer.
9 months ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions