+91-87964 74404
FlagBACK
Question icon
Grade 12th passAlgebra

if x is a real number and [x+(11/100)] + [x+(12/100)] + …...............[x+(99/100)] = 765 then find the value of [900] – [100x] where [.] represents greatest integer.

Profile image of krishika
6 Years agoGrade 12th pass
Answers icon

1 Answer

Profile image of Kushal Upadhyay
6 Years ago
(X+11/100)+(X+12/100)+....+(X+99/100)=765
Hence (100x+11+100x+12+100x+13+...+100x+99)/100=765
Now,there are 89 100x terms and by cross multiplying
76500=8900x+4895
Now we get,X=8.04
900-(100×8.04). Hence we get 96 as answer.

Other Related Questions on algebra

question mark
What is a binomial expression?
algebra
1 Answer Available

Last Activity: 2 Years ago

question mark
Can we divide two vectors? If this is possible then how?
algebra
1 Answer Available

Last Activity: 2 Years ago

question mark
How do you write “the product of 18 and q” as an algebraic expression?
algebra
1 Answer Available

Last Activity: 2 Years ago

question mark
दहावीच्या आय सी एस इ विद्यार्थ्यांनी पुढे काय करायला पाहिजे
algebra
1 Answer Available

Last Activity: 3 Years ago

question mark
Find the least number of square tiles by which the floor of a room of dimensions 16.58 m and 8.32 m can be covered completely. why HCF and not LCM as “least” keywor dis given?
algebra
1 Answer Available

Last Activity: 3 Years ago