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if roots of a equation x^2-(a+3)x+3a-1=0 are integarl then the value of a is

anagha , 7 Years ago
Grade 12th pass
anser 1 Answers
jagdish singh singh

Last Activity: 7 Years ago

\hspace{-0.7 cm}$ Given $x^2-(a+3)x+3a=1\Rightarrow (x-a)(x-3) = 1=1\cdot 1 = -1 \cdot -1 $\\\\ $\bullet$ If $x-a=1$ and $x-3 = 1\;,$ Then we get $a=3$\\\\ $\bullet$ If $x-a=-1$ and $x-3 = -1\;,$ Then we get $a=3$

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