if a = log 3 x 2 + (log 3 x) 2 – 10 and x a = 1/x 2 then x = ? a.

Question

if a = log 3 x 2 + (log 3 x) 2 – 10 and x a = 1/x 2 then x = ? a.

Shanmukha · Answer

From x a = 1/x 2 x a +2 =1 a+2=0 we get a = -2 Now put log 3 x=t and sub. a=-2 in the given equation. You will get a quadratic equation. Find roots and sub. t and find x ANs: x = 1/81 or 9

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if a = log 3 x 2 + (log 3 x) 2 – 10 and x a = 1/x 2 then x = ? a.

if a = log₃x²+ (log₃ x)² – 10 and x^a= 1/x² then x = ?
a.

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if a = log 3 x 2 + (log 3 x) 2 – 10 and x a = 1/x 2 then x = ? a.

if a = log3x2 + (log3 x)2 – 10 and xa = 1/x2 then x = ?a.

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if a = log₃x²+ (log₃ x)² – 10 and x^a= 1/x² then x = ?
a.