If a,b belong to [0,pie] and the equation x^2 +4 + 3sin(ax +b) – 2x =0 has at least one solution , then find the value of ( a +b)

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siddharth gupta · Answer

3sin(ax+b) belongs to [-3,3] , on the other hand the quadratic x 2 -2x+4 has its minimum value at x=1 equal to 3, (using the concept coefficient of x 2 > 0 and D WITH REGARDS SIDDHARTH GUPTA

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If a,b belong to [0,pie] and the equation x^2 +4 + 3sin(ax +b) – 2x =0 has at least one solution , then find the value of ( a +b)

If a,b belong to [0,pie] and the equation x^2 +4 + 3sin(ax +b) – 2x =0 has at least one solution , then find the value of ( a +b)

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If a,b belong to [0,pie] and the equation x^2 +4 + 3sin(ax +b) – 2x =0 has at least one solution , then find the value of ( a +b)

If a,b belong to [0,pie] and the equation x^2 +4 + 3sin(ax +b) – 2x =0 has at least one solution , then find the value of ( a +b)

1 Answers

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Other Related Questions on Algebra

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