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If 1 2 , w, w are the cube roots of unity, then prove the following : (1+w) (1+w^2 ) (1+w^7 ) (1 +w^*8)=1
we know that w3 = 1and 1 + w + w2 = 0therefore w7 = wand w8 = w2 given expression becomes(1+w)2 (1+w2 )2=[(1+w) (1+w2 )]2=(1 + w3 + w + w2)2=(1 + 0 )2=1
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