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Grade: 12

                        

If 1 2 , w, w are the cube roots of unity, then prove the following : (1+w) (1+w^2 ) (1+w^7 ) (1 +w^*8)=1

3 years ago

Answers : (1)

Ritesh Khatri
76 Points
							
we know that w3 = 1
and 1 + w + w2 = 0
therefore w7 = w
and w8 = w2
 
given expression becomes
(1+w)2 (1+w2 )2
=[(1+w) (1+w2 )]2
=(1 + w3 + w + w2)2
=(1 + 0 )2
=1
3 years ago
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