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GIVEN that log 2 3=a ,log 3 5=b,log 7 2=c then find log 140 63=(1+2ac)/(2c+abc+1)

GIVEN that log23=a ,log35=b,log72=c then find log14063=(1+2ac)/(2c+abc+1)
 

Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
log 140 63 = log2 (3*3*7) / log 2 (2*2*5*7)
 
Now on simplifying you get the answer as 
 
(2ac + 1) /(abc + 2c + 1)
 
Hope it helps

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