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GIVEN that log23=a ,log35=b,log72=c then find log14063=(1+2ac)/(2c+abc+1)
log 140 63 = log2 (3*3*7) / log 2 (2*2*5*7) Now on simplifying you get the answer as (2ac + 1) /(abc + 2c + 1) Hope it helps
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