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`        For any cubic polynomial if f(1)=1f(2)=2f(3)=4Then find f(6) `
one year ago

Agrata Singh
208 Points
```							Ket the cubic expression be x3+bx2+cx+df(1)=1+b+c+d=1b+c+d=0..---(i) f(2)=8+4b+2c+d=24b+2c+d+6=0..--(ii) f(3)=27+9b+3c+d=49b+3c+d+23=0...--(iii) Solve these eqns for b c d and put in to find f(x)Hopefully this helps you
```
one year ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions