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find the value of log3log3log9log729+3log3 basev3

Kumkum , 10 Years ago
Grade 12
anser 1 Answers
Arun Kumar

Last Activity: 10 Years ago

Hello Student

9^3=729
log9(729)=3 3*logv3((v3)^2)=3*2=6
log3(3)=1
log3(1)=0
log3log3log9729+3logv33=6

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

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