ArunApproved Tutor Answer8 Years agoDear Sameer For nth term Tn = (1³ + 2³ +3³+..,..+n³)/(1 +3+5+....(2n-1)) Tn = n²(n+1)²/[4 *(n/2)(2n)] Tn = (n+1)²/4 Tn = (n² + 1 + 2n) /4 Now Sn = sigma Tn Now you can solve RegardsArun (askIITians forum expert)