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Find the sum of n terms 1 3 /1+1 3 +2 3 /1+3+1 3 +2 3 +3 3 /1+3+5+....

Find the sum of n terms 13/1+13+23/1+3+13+23+33/1+3+5+....

Grade:11

1 Answers

Arun
25750 Points
6 years ago
Dear Sameer
 
For nth term
 
Tn = (1³ + 2³ +3³+..,..+n³)/(1 +3+5+....(2n-1))
 
Tn = n²(n+1)²/[4 *(n/2)(2n)]
 
Tn = (n+1)²/4
 
Tn = (n² + 1 + 2n) /4
 
Now 
 
Sn = sigma Tn
 
Now you can solve 
 
 
Regards
Arun (askIITians forum expert)

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