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Find the eccentric angle of the point (x1,y1) on the ellipse x2/6 + y2/2=1 whose distance from the centre is 2.

Nishtha Gahlot , 8 Years ago
Grade 11
anser 3 Answers
Rahul Thakur

Last Activity: 8 Years ago

let the eccentric angle be t ;   a2 = 6  ;  b2 = 2
x1= acost     x2= asint
(acost)2 + (bsint)2  =4
 
t  = +45 ; −45

Shubhranshu Pattnaik

Last Activity: 7 Years ago

Let t be the eccentric angle , a2=6 , b2=2 and point p(acost,asint).
It’s given distance of point from center(0,0) is 2 so by using distance formula, 
                          (acost)2+(bsint)2=4 
                           On solving we get :
                          cos2t=1/2 
                         So t= 45

ankit singh

Last Activity: 4 Years ago

We know, 6Π​+θ=π
⇒θ=65π​ in anticlockwise direction
So, eccentric angle is −65π
thank u regards
ankit singh manit bhopl​

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