badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

Find the eccentric angle of the point (x 1 ,y 1 ) on the ellipse x 2 /6 + y 2 /2=1 whose distance from the centre is 2.

4 years ago

Answers : (3)

Rahul Thakur
24 Points
							
let the eccentric angle be t ;   a= 6  ;  b2 = 2
x1= acost     x2= asint
(acost)+ (bsint)2  =4
 
t  = +45 ; −45
4 years ago
Shubhranshu Pattnaik
21 Points
							
Let t be the eccentric angle , a2=6 , b2=2 and point p(acost,asint).
It’s given distance of point from center(0,0) is 2 so by using distance formula, 
                          (acost)2+(bsint)2=4 
                           On solving we get :
                          cos2t=1/2 
                         So t= 45
2 years ago
ankit singh
askIITians Faculty
596 Points
							
We know, 6Π+θ=π
θ=65π in anticlockwise direction
So, eccentric angle is 65π
thank u regards
ankit singh manit bhopl
2 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details