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Find the eccentric angle of the point (x 1 ,y 1 ) on the ellipse x 2 /6 + y 2 /2=1 whose distance from the centre is 2. Find the eccentric angle of the point (x1,y1) on the ellipse x2/6 + y2/2=1 whose distance from the centre is 2.
let the eccentric angle be t ; a2 = 6 ; b2 = 2x1= acost x2= asint(acost)2 + (bsint)2 =4 t = +45 ; −45
Let t be the eccentric angle , a2=6 , b2=2 and point p(acost,asint).It’s given distance of point from center(0,0) is 2 so by using distance formula, (acost)2+(bsint)2=4 On solving we get : cos2t=1/2 So t= 45
We know, 6Π+θ=π⇒θ=65π in anticlockwise directionSo, eccentric angle is −65πthank u regards ankit singh manit bhopl
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