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Find an interval in which root of the equation x3-2x-1 =0 lie? Find an interval in which root of the equation x3-2x-1 =0 lie?
You see if we take x=-1 then the left hand side becomes zero.So x+1=0.Following this rule we shall factorize the equation.x3-2x-1=0Or,x3+x2-x2-x-x-1=0or,x2(x+1)-x(x+1)-1(x+1)=0Or,(x+1)(x2-x-1)=0so either x=-1 or So the roots lie between -1 to (1+root5)/2.Please approve the answer if you are helped.
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