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Grade: 11

                        

Can anyone solve this. Please solve this question with proper description.

2 years ago

Answers : (1)

Pragya
24 Points
							tan^2z=(sin(x+y)/2 *sin(x-y)/2)/cos(x+y)/2*cos(x-y)/2tan^2z=(cosy-cosx)/(cosx+cosy)Now by componendo dividendo,(tan^2z +1)/(tan^2z -1)=-cosy/cosx-1/cos2z=cosy/(-cosx)Cosx=cosy*cos2z
						
2 years ago
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