all the roots of x(x+1)(x+2)......(x+n) where n is a natural no are: a) b)1/n! c) d)none

Question

all the roots of x(x+1)(x+2)......(x+n) where n is a natural no are: a) b)>1/n! c) d)none

RISHABH CHAURASIA · Answer

Option a and c are not seen here. x=0 itself is a root of this expression. and if we take x= -n then x+n=0 and so -n will be a root. if n=1 then -1(-n) is definitely not greater than 1(1/n). there fore option b is also wrong. so i feel that this question is incoplete and with the available information i can say that it is none.

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all the roots of x(x+1)(x+2)......(x+n) where n is a natural no are: a) b)>1/n! c) d)none

all the roots of x(x+1)(x+2)......(x+n) where n is a natural no are:
a)
b)>1/n!
c)
d)none

1 Answers

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all the roots of x(x+1)(x+2)......(x+n) where n is a natural no are: a) b)>1/n! c) d)none

all the roots of x(x+1)(x+2)......(x+n) where n is a natural no are:a)b)>1/n!c)d)none

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all the roots of x(x+1)(x+2)......(x+n) where n is a natural no are:
a)
b)>1/n!
c)
d)none