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a+b+c=0 find to 1/(a+b)(b+c) +1/(a+c)(b+a) +1/(c+a)(c+b)=?

a+b+c=0 find to 1/(a+b)(b+c) +1/(a+c)(b+a) +1/(c+a)(c+b)=?

Grade:10

3 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
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Aditya Gupta
2081 Points
4 years ago
saurabhs answer is WRONG as usual.
1/(a+b)(b+c) +1/(a+c)(b+a) +1/(c+a)(c+b)= (c+a+b+c+a+b)/(a+b)(b+c)(c+a)
= 2(a+b+c)/(a+b)(b+c)(c+a)
= 0
kindly approve :)
SAMBHAV MISHRA
38 Points
4 years ago
@aditya gupta you are an idiot.. sourav is far better than you.. by the way i hope you got to know that arithmatic means question given from me.... 
 

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