the equation whoose roots are sec2a & cosec2a
can be{where 2 is the power of sec &cosec}.

Question

the equation whoose roots are sec2a & cosec2a can be{where 2 is the power of sec &cosec}.

Nehal Wani · Answer

Sum Of Roots =(1/sin 2 a)+(1/cos 2 a)=(sin 2 a+cos 2 a)/(sinacosa) 2 =4/(sin2a) 2 =4cosec 2 2a Product Of Roots =(1/sin 2 a)(1/cos 2 a)=1/(sinacosa) 2 =4/(sin2a) 2 =4cosec 2 2a X 2 -(Sum Of Roots)x+Product Of Roots=0 X 2 -(4cosec 2 2a)x+4cosec 2 2a=0

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the equation whoose roots are sec2a & cosec2a can be{where 2 is the power of sec &cosec}.

the equation whoose roots are sec2a & cosec2a
can be{where 2 is the power of sec &cosec}.

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