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the equation whoose roots are sec2a & cosec2a can be{where 2 is the power of sec &cosec}.

the equation whoose roots are sec2a & cosec2a
can be{where 2 is the power of sec &cosec}.

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1 Answers

Nehal Wani
21 Points
11 years ago

Sum Of Roots
=(1/sin2a)+(1/cos2a)=(sin2a+cos2a)/(sinacosa)2=4/(sin2a)2=4cosec22a

Product Of Roots
=(1/sin2a)(1/cos2a)=1/(sinacosa)2=4/(sin2a)2=4cosec22a

X2-(Sum Of Roots)x+Product Of Roots=0

X2-(4cosec22a)x+4cosec22a=0

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