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Dear shefali
probability of same boy doesn't receive both pens = 1 - probabilty of any boy receive both pens
since all the student recieves same number of article.so each one get (10+2)/3 =4
number of ways in which 10 books and 2 pen is distributed to 3 student is =12C4 8C4 4C4
now find the number of ways such that any boy recieve the both pen...
select one boy from 3 and give both pen to him in = 3C1 * 1 ways
rest two article can be given to this boy in = 10C2 ways
other 2 boys will get article in 8C4 *4C4 ways
so number of ways such that any boy recieve the both pen= 3C1 * 1*10C2 *8C4 *4C4
so required probability = 1- 3C1 * 1*10C2 *8C4 *4C4 / 12C4 8C4 4C4
=8/11
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
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