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# factorize(x+1)(x+2)(x+3)(x+6)-3x2

Grade:10

## 1 Answers

Badiuddin askIITians.ismu Expert
148 Points
11 years ago

Dear ajinkya

(x+1)(x+2)(x+3)(x+6)-3x2

(x+1)(x+1+1)(x+3)(x+3+3)-3x2

[(x+1)2 +(x+1)] [(x+3)2 +3(x+3)]-3x2

(x+1)2(x+3)+3(x+1)2(x+3) + (x+3)2(x+1)  + 3(x+1)(x+3)  - 3x2

(x+1)2(x+3)+2(x+1)(x+3)(2x+3) + 3(x+1)(x+3)  - 3x2

(x+1)2(x+3)+2(x+1)(x+3)(2x+3) +(2x+3)2 -(2x+3)2 - 4x2

[(x+1)(x+3)  +(2x+3)]2 - 4x2

[(x+1)(x+3)  +(2x+3) - 2x][(x+1)(x+3)  +(2x+3) + 2x]

brackets contain quadretic equation  you can easly factorize them

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