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factorize
(x+1)(x+2)(x+3)(x+6)-3x2
Dear ajinkya
(x+1)(x+1+1)(x+3)(x+3+3)-3x2
[(x+1)2 +(x+1)] [(x+3)2 +3(x+3)]-3x2
(x+1)2(x+3)2 +3(x+1)2(x+3) + (x+3)2(x+1) + 3(x+1)(x+3) - 3x2
(x+1)2(x+3)2 +2(x+1)(x+3)(2x+3) + 3(x+1)(x+3) - 3x2
(x+1)2(x+3)2 +2(x+1)(x+3)(2x+3) +(2x+3)2 -(2x+3)2 - 4x2
[(x+1)(x+3) +(2x+3)]2 - 4x2
[(x+1)(x+3) +(2x+3) - 2x][(x+1)(x+3) +(2x+3) + 2x]
brackets contain quadretic equation you can easly factorize them
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