Flag Algebra> permutations...
question mark

Number of words of 4 letters that can be formed with the letter of the word IITJEE is...............

sridhar yelkur , 11 Years ago
Grade 12
anser 14 Answers
Maruthi Sirisilla

Last Activity: 11 Years ago

the answer is 468

Anshuman Chandel

Last Activity: 11 Years ago

102

shetti swamy patel

Last Activity: 11 Years ago

answer is 256

shubham sharma

Last Activity: 11 Years ago

Ans. Is 14!!!

» four distinct letters= (4C4)

»Of form (aabb)= (2C1).(4C2)

»Of form aabc= (2C2)

So 0n adding it comes 14.

 

revathy t.nair

Last Activity: 11 Years ago

is that 6*6*6*6=1296? is that the answer?

Sandeep Trivedi

Last Activity: 11 Years ago

72

jitender lakhanpal

Last Activity: 11 Years ago

there will be following cases

1) words form by letters I,T,J,E

we will use permutation

4! =24

2) words form by only I,I,E,E

there would be following arrangement

IIEE   another word by flipping the letters I,E

IEEI another word by flipping the letters

EIEI  another word by flipping the letters

it makes total of 6

3) words formed by 2 I''S T,J,E

first select 2 places out of four so we use combination

3C2  and then arrange 3 letters in 2 places

so finally we get

4C2*6 = 36

4) words formed by 2 E''S  AND T,J,E

so again 36

so add all cases you will get the answer

 

We are all IITians and here to help you in your IIT JEE preparation.

Now you can win by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar : Click here to download the toolbar.. 

 

Thanks and Regards

Jitender

(askIITians expert)

Krrish .

Last Activity: 10 Years ago

184

ashwin26

Last Activity: 10 Years ago

IITJEE Can be written as " II ", "T" , "J" , "EE" here there are two sets of repeated combinations(I,J) .now the four letter words can be categorised into (i)two similar,another two similar 2C1*(4!/(2!*2!)) ways. (ii)two similar , 1 different , another different 2C1*(3C2)*(4!/2!) ways (iii)All different 4! ways so the total number of 4 letter words= 12+72+24=108

GOPI

Last Activity: 10 Years ago

90

KARTHIK

Last Activity: 10 Years ago

there will be following cases 1) words form by letters I,T,J,E we will use permutation 4! =24 2) words form by only I,I,E,E there would be following arrangement IIEE another word by flipping the letters I,E IEEI another word by flipping the letters EIEI another word by flipping the letters it makes total of 6 3) words formed by 2 I``S T,J,E first select 2 places out of four so we use combination 3C2 and then arrange 3 letters in 2 places so finally we get 4C2*6 = 36 4) words formed by 2 E``S AND T,J,E so again 36 so add all cases you will get the answer

venkatesh vadde

Last Activity: 10 Years ago

24

venkatesh vadde

Last Activity: 10 Years ago

no restriction means digits can be repeated if first place is filled by I then possible arrangements are 5!/2! if first place is filled by T then possible arrangements are 5!/(2!*2!) if first place is filled by J then possible arrangements are 5!/(2!*2!) if first place is filled by E then possible arrangements are 5!/2! total no of arrangements are 60+30+30+60=180

goutham

Last Activity: 9 Years ago

102
 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...