Number of all five digits numbers divisible by 4 that can formed from 0,1,2,3,4 without repetition is

72

96

hi shubham

there would be 5 cases in which the number is divisible by 4

when the last 2 digits are

04,40,12,32,20

now we have to find the number of ways in which we can arrange the first three digits in all the cases

let us take when the last 2 digits are 04

we have 1,2,3 and we have to arrange it in first 3 digits we can do it in 3! ways (without repition we will use PERMUTATION

similar are the cases for 40 and 20

but for 12 ,32 the number of cases are 4 ways each

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Jitender

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Hey jitendra i wanted to know how you finded those five cases

what will be the cases when it will be asked for four digit number .basically I want to know the trick to solve these type of questions..

hi shubhum

it is very evident in this case that the last two digits will be divisible by 4

the basic divisibility criteria of 4

likewise we we can find the cases for divisibilty of 8 , 5

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Jitender

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52

26 ways ....ends with 04-----3! ....ends with 40-----3! ---ends with 20......3! ....ends with 12------4(3!-2!) ...ends with 32.......4(3!-2!)

i just want to confirm that only five cases are possible: 04 40 20 12 32..............................24????

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