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find the number of ways in which a mixed double game can be organized amongst 9 married couples if no husband or wife play in the same game ?

find the number of ways in which a mixed double game can be organized amongst 9 married couples if no husband or wife play in the same game ?

Grade:12th Pass

2 Answers

omkar rudrawar
16 Points
7 years ago

its simple 9*8=72

jitender lakhanpal
62 Points
7 years ago

hi zaid ignore the previous post 

you can take the analogy of function mapping 

take 9 husbands as X and 9 wives as Y   X TO Y

now total number of ways in which the game can be organised is  total number of injections (P(9,9))

and there is only one way in which the husband and wives are pair together

so 

the number of ways in which a mixed double game can be organized amongst 9 married couples if no husband or wife play in the same game  is P(9,9) - 1 

OR 9! - 1 for further explanation i am als giving the attachment


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