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7 different coins are to be divide amongst 3 persons. If now 2 of the persons receive the same no of coins but each receives at least 1 coin and none is left over, then the no of ways in which the division may be made is ?
Dear jee king
there are 6 possibility
1+2+4 =7
and permutation for this is 3! =6
person who get only one prize ,can get in 7C1 =7 ways
person who get two prize ,can get in 6C2 =15 ways
person who get four prize ,can get in 4C4 =1 ways
total ways =6! * 7*15*1
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