Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
the sides of a quad taken at random are
x+3y-7=0 x-2y-5=0
3x+2y-7=0 7x-y+17=0
obtain the equation of the diagonals
Dear Abhishekh,The lines intersect the x axis at a distance 7 , 5 , 7/3 , -17/7 and the slopes of the lines are -1/3 , 1/2 , -3/2 , 7hence the sides taken in order are x+3y-7 = 0 7x-y+17=0 3x+2y-7=0 x-2y-5=0Solving the equations one by one we get their point of intersections.and then making the equations of the diagonals we ge:-1st Diagonal is 4x+5y-7=0,Similarly the second Diagonal can be found.Regards.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !