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the sides of a quad taken at random are
x+3y-7=0 x-2y-5=0
3x+2y-7=0 7x-y+17=0
obtain the equation of the diagonals
Dear Abhishekh,The lines intersect the x axis at a distance 7 , 5 , 7/3 , -17/7 and the slopes of the lines are -1/3 , 1/2 , -3/2 , 7hence the sides taken in order are x+3y-7 = 0 7x-y+17=0 3x+2y-7=0 x-2y-5=0Solving the equations one by one we get their point of intersections.and then making the equations of the diagonals we ge:-1st Diagonal is 4x+5y-7=0,Similarly the second Diagonal can be found.Regards.
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