A box contains 6 nails and 10 nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random, then the probability that it is rusted or a nail is.........

Dear Shiva,

P(rusted) = 8/16

P(nail) = 6/16

P(rusted and nail) = 3/16

P(A intersection B) = 8/16 + 6/16 - 3/16;

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