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For all positive integers n for which 3 < 100^(1/n) <5 please tell detailed method also!!
For all positive integers n for which
3 < 100^(1/n) <5
please tell detailed method also!!
3<1001/n<5 3n<100<5n So, 3n<100 and 100<5n i.e.n=1,2,3,4 and n=3,4,5,6,7....................................... Form both the values of n we got above we have 3&4 common value of n in both cases. Hence n=[3,4] Plz. approve my answer by clicking Yes given below, if u loved it... Plz/.... AND BEST OF LUCK
3<1001/n<5
3n<100<5n
So, 3n<100 and 100<5n
i.e.n=1,2,3,4 and n=3,4,5,6,7.......................................
Form both the values of n we got above we have 3&4 common value of n in both cases.
Hence n=[3,4]
AND BEST OF LUCK
3<100^1/n<5 so 3^n,100,5^n is true for n=3 and 4 P S Dave M.Sc BEd (maths)
3<100^1/n<5
so 3^n,100,5^n
is true for n=3 and 4 P S Dave M.Sc BEd (maths)
thnxs
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