askIITiansexpert nagesh
Last Activity: 15 Years ago
Dear sudarshan gupta,
Given, ax2+bx+c+k=0, has two distinct positive roots for each k, where k is real
let, p,q be those roots
then p and q are distinct and positive, hence product should be always positive for all real k
but pq=(c+k)/a, which can take both positive and negative values as k changes.
So there will be no quadratic equation ax2+bx+c = 0, such that ax2+bx+c+k=0 has 2 distinct positive roots for each real k.
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nagesh