Sum of n terms of the sequence [ {1/1+1^2+1^4}+{2/1+2^2+2^4}+{3/1+3^2+3^4}+-----------------------

Σ ( n + n² + n⁴) = Σn + Σ n² + Σ n⁴ 

Σ n = n(n+1)/2

Σ n² = n(n+1)(2n+1)/6

Σ n⁴ = n(n+1)(2n+1)(3n²+3n-1)/30

So sum = {n(n+1)/2} + {n(n+1)(2n+1)/6} + {n(n+1)(2n+1)(3n²+3n-1)/30}

So the sum can be calculated in this way.