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Sum of n terms of the sequence [ {1/1+1^2+1^4}+{2/1+2^2+2^4}+{3/1+3^2+3^4}+-----------------------
Σ ( n + n2 + n4) = Σn + Σ n2 + Σ n4
Σ n = n(n+1)/2
Σ n2 = n(n+1)(2n+1)/6
Σ n4 = n(n+1)(2n+1)(3n2+3n-1)/30
So sum = {n(n+1)/2} + {n(n+1)(2n+1)/6} + {n(n+1)(2n+1)(3n2+3n-1)/30}
So the sum can be calculated in this way.
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