jitender lakhanpal
Last Activity: 13 Years ago
Dear Abhisek,
x2 + ax + b
for integer root discriminant must be a perfect square
a2 -4b
a = 1+d
b= 1+2d where d is the common difference
now putting the value
1+d2 +2d -4-8d
d2 -6d -3
(d-3)2 -12
now d =7,and -1
so a = 0 and b = -1 for d = -1
a = 8 and b = 15 d = 7
x2 - 1 is one monic
and x2 + 8x + 15 is other
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jitender