Solve this equation[(2x3-3x2+x+1)/(2x3-3x2-x-1)]=[(3x3-x2+5x-13)/(3x3-x2-5x+13)]

Dear Suhas,

 [(2x³-3x²+x+1)/(2x³-3x²-x-1)]=[(3x³-x²+5x-13)/(3x³-x²-5x+13)]

now cross multiply you will see this will get reduced 

 2x³-3x²+x+1)*(3x³-x²-5x+13) = (3x³-x²+5x-13)*(2x³-3x²-x-1)

now it is very clear that the terms of x⁶  and other terms will also get cancelled 

and the equation get reduced to solvable form

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