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How can we write log n (v / v0) = 2x as v = v0e2x ? Please explain.
Dear Manish Sahu,
This is a rule of logarithm that 1/ln (x) becomes ex .
This is the same thing that has happened here .
Logn has gone as a denominator to the other side making it exponential !!
Hope this helped you immensely..
All the Very Best & Good Luck to you ...
Regards,
AskIITians Expert,
Godfrey Classic Prince
IIT-Madras
Please do not forget to approve my answer if you liked it by clicking on "Yes" given below...!!
log v - log vo = 2x (log to base n)
lnv - lnvo = 2x ln (n)
ln (v/vo) = 2x ln(n)
e^2xln(n) = v/vo
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