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Hi everyone....solve this !!!
find the range and domain of the function f(x) = (2x+1)/(x-1) and also find its inverse.
This function is not defined for x = 1. So, domain of the function is R -{1}. Now, for finding the range Let,(2x+3)/(x-1) = y => 2x + 3 = yx - y => yx - 2x = y + 3 => (y - 2)x = y + 3 => x =(y+3)/(t-2) So, y cannot assume value 2 Range of f(x) is R - {2}. Inverse is y =(x+3/x-2) .
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