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solve the equation x^3+67x-126=0 and pls give a generalised method of solving cubics,
thank u
theres no method of solving cubic eqn u have to put values like 1,2,-1,-2 etc and find out the most appropriate one
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i think i doesn't have any solution.Generally in cubic we try to get factors that make eqn=0Then we solve by factorising it.But sometimes we should put the values of x as 1,-1,2,-2,3,-3.Mostly you will get an idea which value to put. Like here i put x=2we get 8+134-126 but that's not = to 0 . putting 1or -1 will not make a total to cancel 126. similarly if you'll put values 3,-3 or greater than that,you'll get total much above 126,so you'll not be able to cancel. Now take the equation:
x^3-67x+126=0 (different than the question one)here if you put x=2 you'll get 8-134+126=126-126=0
This is the method i want to convey it is helpful at times when you are not able to get by factorisation method.ALL THE BEST
its easy just pu thte factors of the constant then u wil get the root
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