SPARSH JAUHARI
Last Activity: 13 Years ago
i think i doesn't have any solution.Generally in cubic we try to get factors that make eqn=0
Then we solve by factorising it.But sometimes we should put the values of x as 1,-1,2,-2,3,-3.Mostly you will get an idea which value to put.
Like here i put x=2
we get 8+134-126 but that's not = to 0 .
putting 1or -1 will not make a total to cancel 126. similarly if you'll put values 3,-3 or greater than that,you'll get total much above 126,so you'll not be able to cancel.
Now take the equation:
x^3-67x+126=0 (different than the question one) here if you put x=2 you'll get 8-134+126=126-126=0
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This is the method i want to convey it is helpful at times when you are not able to get by factorisation method.
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