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A(x)=[cosx -sinx 0 sinx cosx 0 0 0 1] then A(x)A(y)=?

A(x)=[cosx -sinx 0


          sinx cosx 0


           0     0     1]


then A(x)A(y)=?

Grade:11

2 Answers

Dipanwita Bhattacharjee
32 Points
10 years ago

[cosx  -sinx  0      [cosy  -siny  0

 sinx  cosx   0        siny  cosy   0

    0      0     1]         0      0     1]

using matrix multiplicatiom,

= [cos(x+y)   -sin(x+y)     0

   sin(x+y)     cos((x+y)   0

       0                0           1]

Gurwinder Kaur
65 Points
10 years ago

 

[cosx  -sinx  0      [cosy  -siny  0

 sinx  cosx   0        siny  cosy   0

    0      0     1]         0      0     1]

using matrix multiplicatiom,

= [cos(x+y)   -sin(x+y)     0

   sin(x+y)     cos((x+y)   0

       0                0           1]

plz approve if u like....

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