Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A wheel requires certain recolutions to cover a distance.If the circumference of wheel is incresed by 2o percent what is the reduction in no of revolutions in percent

A wheel requires certain recolutions to cover a distance.If the circumference of wheel is incresed by 2o percent what is the reduction in no 


of revolutions in percent

Grade:10

1 Answers

pushpak sahu
14 Points
10 years ago

REDUCTION IN REVOLUTION WILL BE :-   16.66%   APPROX

 

LET THE CIRCUMMFRENCE OF THE WHEEL BE - X  m

SO CIRCUMFRENCE OF THE INCREASED WHEEL - (100+20)% OF  X = 6X/5  m.

No . OF REVOLUTIONS REQUIRED TO COVER 6X/5 m WILL BE = 1

No. OF REVOLUTIONS FOR X m WILL BE =                    X                    = 5/6

                                                                            6X/5

SO REDUCTION IN REVOLUTION WILL BE  = 1- 5/6  =                1               =  16.66%  APPROX

                                                                                           6

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free