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solve for x; iflog 7(x3+7)-log7(x+3)=2

Prerona Gaine , 13 Years ago
Grade 12
anser 1 Answers
vikas askiitian expert

Last Activity: 13 Years ago

log 7(x3+7)-log7(x+3)=2

log(x3+7)/log7 - logx+3/log7 = 2

logx3+7 - logx+3 = 2log7

logx3+7/x+3 = log49

x3+7 = 49x + 49*3

x3 -49x - 20*7 = 0

x3 - 49x - 140 = 0

now solve for x

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