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Grade: 12
```
If log cos x sin x>=2 and 0 π then sin x is in the interval (a)[(5 1/2 -1)/2,1] (b)(0,5 1/2 -1)/2] (c)[0,1/2] (d)none

```
11 years ago

## Answers : (1)

sahil doshi
8 Points
```							logcos xsin x >=2
sin x >= cos2x
sin x >= 1 - sin2x
sin2x + sin x - 1 >= 0
[sin x - (51/2-1) / 2] * [sin x - (-51/2-1) / 2] >= 0
now, sin x > -1
therefore [sin x - (-51/2-1)/2] > 0       { 51/2 ≈ 2        therefore    -(-51/2-1)/2 ≈ 1.5}
therefore [sin x - (51/2-1) / 2] should be > 0
sin x > (51/2-1) / 2]
and sin x lies between [-1,1]
(a)[(51/2-1)/2,1]
```
11 years ago
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