the no of distict 4 digit nos. which have at most 2 distinct digits?
shruti gupta , 14 Years ago
Grade 11
Algebra> permutation and combination...
1 Answers
Chetan Mandayam Nayakar
Last Activity: 14 Years ago
The last digit cannot be zero. Therefore there are 9 possible choices. Another digit can independently have 10 different choices and the remaining two digits are fixed. Thus, the answer is 9*10 = 90
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