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Grade 12th PassAlgebra

In the expansion of align=absMiddle , the term which does not contain x is :
10C0
10C7
10C4
none

Profile image of VISHWESH RAVI
16 Years agoGrade 12th Pass
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1 Answer

Profile image of Badiuddin askIITians.ismu Expert
16 Years ago

Dear Vishwesh

simplyfy the given expression

it will become

 {(x1/3 +1) -(x-1 + x-1/2)}10

={x1/3 +1 -x-1 - x-1/2}10

use multinominal theorem and find general term of series

=10!/p!q!r!s! [(x1/3)p(1)q( -x-1 )r(- x-1/2 )s]

=10!/p!q!r!s! [(xp/3 -r-s/2](-1)r+s   where p+q+r+s =10

for the term does not contain x

   p/3 -r-s/2 =0

now find out all possible value

put p=r=s=0

so q=10

so general term become

10C10  or 10C0

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Badiuddin