# In the expansion of , the term which does not contain x is :       1. 10C0       2. 10C7       3. 10C4       4. none

Grade:12th Pass

## 1 Answers

Badiuddin askIITians.ismu Expert
148 Points
13 years ago

Dear Vishwesh

simplyfy the given expression

it will become

{(x1/3 +1) -(x-1 + x-1/2)}10

={x1/3 +1 -x-1 - x-1/2}10

use multinominal theorem and find general term of series

=10!/p!q!r!s! [(x1/3)p(1)q( -x-1 )r(- x-1/2 )s]

=10!/p!q!r!s! [(xp/3 -r-s/2](-1)r+s   where p+q+r+s =10

for the term does not contain x

p/3 -r-s/2 =0

now find out all possible value

put p=r=s=0

so q=10

so general term become

10C10  or 10C0

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