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Calculate the mass of urea required in making2.5kg of 0.25 molalaqueous solutions

Amandeep kaur , 7 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

0.25 molal means 0.25 moles of solute is present in the 1000 gms of solvent.
But it is fgiven 2.5kg of solvent.
Therefore,
moles = molality*mass of solvent in kg => 0.25*2.5 => 0.625 mol.
mass of urea => 0.625*molar mass of urea => 0.625*60 => 37.5 gms.

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