Arun
Last Activity: 5 Years ago
the car covers the total distance in three phases.
distance in phase 1=s........velocity(v) after this phase:v2=2fs
distance in phase 2:s2=vt=?(2fs) x t
distance in phase 3: s3=putting in third eq of motion:0=v2-2xf/2 xs3
s3=2s...putting the value of v2
now, s+?(2fs) x t+2s=15s
solving this eq: s=2ft2/72