There are multiple chickens and rabbits in a cage. There are 72 heads and 200 feet inside of the cage. How many chickens and rabbits are in there?

Let's solve this problem by setting up a system of equations.

Let's assume the number of chickens is represented by 'C', and the number of rabbits is represented by 'R'.

Each chicken has one head and two feet, while each rabbit has one head and four feet.

Given that there are 72 heads in total, we can write the equation:
C + R = 72 (Equation 1)

Given that there are 200 feet in total, we can write the equation:
2C + 4R = 200 (Equation 2)

Now, we can solve this system of equations to find the values of C and R.

To eliminate C from the equations, we can multiply Equation 1 by 2, and then subtract it from Equation 2:

2C + 4R - (2C + 2R) = 200 - (2 * 72)
2C + 4R - 2C - 2R = 200 - 144
2R = 56
R = 56 / 2
R = 28

Substituting the value of R into Equation 1:
C + 28 = 72
C = 72 - 28
C = 44

Therefore, there are 44 chickens and 28 rabbits in the cage.