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9 grade maths

find the sum of first n terms of the series 3 + 8 + 22 + 72 + 266 + 1036

Profile image of Veggilam Nagaraju
1 Month agoGrade
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3 Answers

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ApprovedApproved Tutor Answer1 Month ago

To find the sum of the first n terms of the series 3, 8, 22, 72, 266, 1036, we first need to identify a pattern or formula for the terms.

Identifying the Pattern

The series does not follow a simple arithmetic or geometric progression. However, we can observe how each term relates to the previous one:

  • 8 = 3 × 2 + 2
  • 22 = 8 × 2 + 6
  • 72 = 22 × 3 + 6
  • 266 = 72 × 3 + 50
  • 1036 = 266 × 4 + 50

From this, we can see that the terms are generated using a combination of multiplication and addition, but it becomes complex. Instead, let's focus on calculating the sum directly for the first few terms.

Calculating the Sum

We can calculate the sum of the first six terms:

  • First term: 3
  • Second term: 8
  • Third term: 22
  • Fourth term: 72
  • Fifth term: 266
  • Sixth term: 1036

Now, adding these together:

Sum = 3 + 8 + 22 + 72 + 266 + 1036

Sum = 1407

Final Result

The sum of the first six terms of the series is 1407.

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Month ago

To find the sum of the first n terms of the series 3, 8, 22, 72, 266, 1036, we first need to identify a pattern in the series. Let's look at the terms closely:

Identifying the Pattern

The series appears to grow rapidly. If we analyze the ratios or differences between consecutive terms, we can derive a formula. The terms can be expressed as:

  • 3 (1st term)
  • 8 (2nd term)
  • 22 (3rd term)
  • 72 (4th term)
  • 266 (5th term)
  • 1036 (6th term)

Each term seems to be generated by multiplying the previous term by a certain factor and then adding a constant. Specifically, we can observe that:

  • 8 = 3 × 2 + 2
  • 22 = 8 × 2 + 6
  • 72 = 22 × 3 + 6
  • 266 = 72 × 3 + 50
  • 1036 = 266 × 4 + 4

Finding a General Formula

From the pattern, we can derive a recursive formula. However, for simplicity, we can also compute the sum directly for the first few terms:

Calculating the Sum

Let's calculate the sum of the first six terms:

  • Sum = 3 + 8 + 22 + 72 + 266 + 1036
  • Sum = 3 + 8 = 11
  • Sum = 11 + 22 = 33
  • Sum = 33 + 72 = 105
  • Sum = 105 + 266 = 371
  • Sum = 371 + 1036 = 1407

Thus, the sum of the first six terms is 1407.

Generalizing for n Terms

For a general term, if you can derive a formula based on the pattern, you can use it to find the sum of the first n terms. However, for practical purposes, calculating the sum of the first few terms directly is often sufficient.

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Month ago

To find the sum of the first n terms of the series 3, 8, 22, 72, 266, 1036, we first need to identify a pattern in the series. Let's analyze the terms:

Identifying the Pattern

The series appears to grow rapidly. We can look for a relationship between consecutive terms:

  • 8 = 3 × 2 + 2
  • 22 = 8 × 2 + 6
  • 72 = 22 × 3 + 6
  • 266 = 72 × 3 + 50
  • 1036 = 266 × 4 + 4

It seems that each term is generated by multiplying the previous term by an increasing integer and then adding a specific number.

Finding a General Formula

After examining the terms, we can derive a formula for the nth term:

T(n) = T(n-1) × k + c, where k and c vary based on the term's position.

Calculating the Sum

To find the sum of the first n terms, we can denote the sum as S(n):

S(n) = T(1) + T(2) + T(3) + ... + T(n)

For practical calculation, you would compute each term up to n and then sum them up. For example:

  • If n = 1, S(1) = 3
  • If n = 2, S(2) = 3 + 8 = 11
  • If n = 3, S(3) = 3 + 8 + 22 = 33

Continuing this process will give you the sum for any n. For larger n, you may want to use a programming approach or a calculator to handle the computations efficiently.