The girl teams , Salma and Mandip are playing a g

Question

The girl teams , Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma ,Salma to Mandip, Mandip to Reshma. Distance between teams and Salma, Salma and Mandip is equal of 6m each what is the distance between teams and Salma?

Arun · Accepted Answer

Let O bethe centre of the circle. A, B and C represent the positions of Reshma, Salmaand Mandip. AB = 6cm and BC = 6cm.Radius OA = 5cm. (given) Draw BM ⊥ AC ABC is an isosceles triangle as AB = BC, M ismid-point of AC. BM isperpendicular bisector of AC and thus it passes through the centre of thecircle. Let AM = y and OM = x then BM = (5-x). In ΔOAM,OA²=OM²+AM² ( by Pythagorastheorem) 5²=x²+ y²—(i)In ΔAMB,AB²=BM² +AM²(by Pythagoras theorem)6²= (5-x)²+y² — (ii)Subtracting (i) from (ii), 36 – 25 = (5-x)² -x² 11 = (25+x²– 2×5×x) - x²11= 25+x²-10x - x²11= 25-10x10x = 14 x= 7/5 Substituting the value of x in (i), we get y²+ 49/25 = 25y² =25 – 49/25y² =(625 – 49)/25y²=576/25 y = 24/5 Thus,AC = 2×AMAC = 2×y AC= 2×(24/5) m = 48/5 m = 9.6 mHence, the Distance between Reshma and Mandipis 9.6 m.

9 grade maths> The girl teams , Salma and Mandip are pla...

The girl teams , Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma ,Salma to Mandip, Mandip to Reshma. Distance between teams and Salma, Salma and Mandip is equal of 6m each what is the distance between teams and Salma?

Judhisir Pradhan , 7 Years ago

Arun

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9 grade maths> The girl teams , Salma and Mandip are pla...

The girl teams , Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma ,Salma to Mandip, Mandip to Reshma. Distance between teams and Salma, Salma and Mandip is equal of 6m each what is the distance between teams and Salma?

Judhisir Pradhan , 7 Years ago

Arun

LIVE ONLINE CLASSES

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