The floor of a building consists of 3000 tiles which are rhombus shaped. The diagonals of each of the tiles are 45 cm and 30 cm. Find the cost of polishing the floor, if cost per sq. m is Rs. 250.

To solve this question, let's break it down step by step:

Area of one tile: Each tile is rhombus-shaped, and the area of a rhombus is given by the formula:

Area = (1/2) × diagonal1 × diagonal2

Here, the diagonals are given as:

Diagonal 1 = 45 cm
Diagonal 2 = 30 cm
Substituting these values into the formula:

Area of one tile = (1/2) × 45 cm × 30 cm = (1/2) × 1350 cm² = 675 cm²

Total area of 3000 tiles: Since there are 3000 tiles, the total area of the floor is:

Total area = 3000 × 675 cm² = 2,025,000 cm²

Convert the area from cm² to m²: 1 m² = 100 cm × 100 cm = 10,000 cm²

So, the total area in m² is:

Total area in m² = 2,025,000 cm² ÷ 10,000 cm²/m² = 202.5 m²

Cost of polishing: The cost of polishing the floor is Rs. 250 per square meter. So, the total cost for polishing the entire floor is:

Total cost = 202.5 m² × Rs. 250/m² = Rs. 50,625

Thus, the cost of polishing the floor is Rs. 50,625.