Dhruv Tyagi
Last Activity: 2 Years ago
Given: diameter of a sphere is decreased by 25%.
We have to find the percentage by which its Curved Surface Area decreases.
Let the radius of the sphere be r.
Then its diameter is 2r.
The Surface area of a sphere = 4πr2
The Curved surface area of the sphere = 4πr2
Now it is given in the question that the diameter of the sphere is decreased by 25% hence a new sphere is formed.
Therefore, the diameter of the new sphere can be written as:
= 2r - (25%) of (2r)
= 2r - (25/100) × (2r)
= 2r - (r/2)
= 3r/2
Radius of the new sphere = 1/2 × 3r/2 = 3r/4
Hence, curved surface area of the new sphere = 4π (3r/4)2
= 4π (9r2/16)
= (9πr2)/4
Now, decrease in the original curved surface area = 4πr - (9πr2)/4
= (16πr2- 9πr2)/4
= (7πr2)/4
So, the percentage decrease in the curved surface area is,
= [(7πr2)/4 × 1/(4πr2)] × 100%
= [7/16] × 100%
= 43.75%