SHAIK AASIF AHAMED
Last Activity: 10 Years ago
Hello student,
Please find the answer to your question below
if x>0,y>0 and z>0
LHS=(1+x)(1+y)(1+z)
=(1+y+x+xy)(1+z)
=(1+x+y+z+xyz)
=1+xyz+(x+y+z)>1+xyz
from the above it is clear that(1+x)(1+y)(1+z)>(1+xyz)